4(y+3)=3y+12

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Solution for 4(y+3)=3y+12 equation: 



4(y+3)=3y+12

We move all terms to the left:

4(y+3)-(3y+12)=0

We multiply parentheses

4y-(3y+12)+12=0

We get rid of parentheses

4y-3y-12+12=0

We add all the numbers together, and all the variables

y=0

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