4(y+3)=4(2y-7)+6y

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Solution for 4(y+3)=4(2y-7)+6y equation: 



4(y+3)=4(2y-7)+6y

We move all terms to the left:

4(y+3)-(4(2y-7)+6y)=0

We multiply parentheses

4y-(4(2y-7)+6y)+12=0



We calculate terms in parentheses: -(4(2y-7)+6y), so:

4(2y-7)+6y

We add all the numbers together, and all the variables

6y+4(2y-7)

We multiply parentheses

6y+8y-28

We add all the numbers together, and all the variables

14y-28

Back to the equation:

-(14y-28)



We get rid of parentheses

4y-14y+28+12=0

We add all the numbers together, and all the variables

-10y+40=0

We move all terms containing y to the left, all other terms to the right

-10y=-40

y=-40/-10

y=+4

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