4(y+3)=4y+12

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Solution for 4(y+3)=4y+12 equation: 


Simplifying
4(y + 3) = 4y + 12

Reorder the terms:
4(3 + y) = 4y + 12
(3 * 4 + y * 4) = 4y + 12
(12 + 4y) = 4y + 12

Reorder the terms:
12 + 4y = 12 + 4y

Add '-12' to each side of the equation.
12 + -12 + 4y = 12 + -12 + 4y

Combine like terms: 12 + -12 = 0
0 + 4y = 12 + -12 + 4y
4y = 12 + -12 + 4y

Combine like terms: 12 + -12 = 0
4y = 0 + 4y
4y = 4y

Add '-4y' to each side of the equation.
4y + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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