4(y+3)=5(3+2y)

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Solution for 4(y+3)=5(3+2y) equation: 



4(y+3)=5(3+2y)

We move all terms to the left:

4(y+3)-(5(3+2y))=0

We add all the numbers together, and all the variables

4(y+3)-(5(2y+3))=0

We multiply parentheses

4y-(5(2y+3))+12=0



We calculate terms in parentheses: -(5(2y+3)), so:

5(2y+3)

We multiply parentheses

10y+15

Back to the equation:

-(10y+15)



We get rid of parentheses

4y-10y-15+12=0

We add all the numbers together, and all the variables

-6y-3=0

We move all terms containing y to the left, all other terms to the right

-6y=3

y=3/-6

y=-1/2

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