4(y+3)=5(y-4)

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Solution for 4(y+3)=5(y-4) equation:


Simplifying
4(y + 3) = 5(y + -4)

Reorder the terms:
4(3 + y) = 5(y + -4)
(3 * 4 + y * 4) = 5(y + -4)
(12 + 4y) = 5(y + -4)

Reorder the terms:
12 + 4y = 5(-4 + y)
12 + 4y = (-4 * 5 + y * 5)
12 + 4y = (-20 + 5y)

Solving
12 + 4y = -20 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
12 + 4y + -5y = -20 + 5y + -5y

Combine like terms: 4y + -5y = -1y
12 + -1y = -20 + 5y + -5y

Combine like terms: 5y + -5y = 0
12 + -1y = -20 + 0
12 + -1y = -20

Add '-12' to each side of the equation.
12 + -12 + -1y = -20 + -12

Combine like terms: 12 + -12 = 0
0 + -1y = -20 + -12
-1y = -20 + -12

Combine like terms: -20 + -12 = -32
-1y = -32

Divide each side by '-1'.
y = 32

Simplifying
y = 32

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