4(y+4)+y=2(y+4)+2

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Solution for 4(y+4)+y=2(y+4)+2 equation: 



4(y+4)+y=2(y+4)+2

We move all terms to the left:

4(y+4)+y-(2(y+4)+2)=0

We add all the numbers together, and all the variables

y+4(y+4)-(2(y+4)+2)=0

We multiply parentheses

y+4y-(2(y+4)+2)+16=0



We calculate terms in parentheses: -(2(y+4)+2), so:

2(y+4)+2

We multiply parentheses

2y+8+2

We add all the numbers together, and all the variables

2y+10

Back to the equation:

-(2y+10)



We add all the numbers together, and all the variables

5y-(2y+10)+16=0

We get rid of parentheses

5y-2y-10+16=0

We add all the numbers together, and all the variables

3y+6=0

We move all terms containing y to the left, all other terms to the right

3y=-6

y=-6/3

y=-2

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