4(y+4)+y=3(y+2)-4

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Solution for 4(y+4)+y=3(y+2)-4 equation: 


Simplifying
4(y + 4) + y = 3(y + 2) + -4

Reorder the terms:
4(4 + y) + y = 3(y + 2) + -4
(4 * 4 + y * 4) + y = 3(y + 2) + -4
(16 + 4y) + y = 3(y + 2) + -4

Combine like terms: 4y + y = 5y
16 + 5y = 3(y + 2) + -4

Reorder the terms:
16 + 5y = 3(2 + y) + -4
16 + 5y = (2 * 3 + y * 3) + -4
16 + 5y = (6 + 3y) + -4

Reorder the terms:
16 + 5y = 6 + -4 + 3y

Combine like terms: 6 + -4 = 2
16 + 5y = 2 + 3y

Solving
16 + 5y = 2 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
16 + 5y + -3y = 2 + 3y + -3y

Combine like terms: 5y + -3y = 2y
16 + 2y = 2 + 3y + -3y

Combine like terms: 3y + -3y = 0
16 + 2y = 2 + 0
16 + 2y = 2

Add '-16' to each side of the equation.
16 + -16 + 2y = 2 + -16

Combine like terms: 16 + -16 = 0
0 + 2y = 2 + -16
2y = 2 + -16

Combine like terms: 2 + -16 = -14
2y = -14

Divide each side by '2'.
y = -7

Simplifying
y = -7

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