4(y+4)-(2y+12)=0

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Solution for 4(y+4)-(2y+12)=0 equation: 



4(y+4)-(2y+12)=0

We multiply parentheses

4y-(2y+12)+16=0

We get rid of parentheses

4y-2y-12+16=0

We add all the numbers together, and all the variables

2y+4=0

We move all terms containing y to the left, all other terms to the right

2y=-4

y=-4/2

y=-2

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