4(y+4)-5=47

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Solution for 4(y+4)-5=47 equation: 



4(y+4)-5=47

We move all terms to the left:

4(y+4)-5-(47)=0

We add all the numbers together, and all the variables

4(y+4)-52=0

We multiply parentheses

4y+16-52=0

We add all the numbers together, and all the variables

4y-36=0

We move all terms containing y to the left, all other terms to the right

4y=36

y=36/4

y=9

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