4(y+4)-8y=28

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Solution for 4(y+4)-8y=28 equation: 



4(y+4)-8y=28

We move all terms to the left:

4(y+4)-8y-(28)=0

We add all the numbers together, and all the variables

-8y+4(y+4)-28=0

We multiply parentheses

-8y+4y+16-28=0

We add all the numbers together, and all the variables

-4y-12=0

We move all terms containing y to the left, all other terms to the right

-4y=12

y=12/-4

y=-3

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