4(y+4)=-2(4y-1)+2y

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Solution for 4(y+4)=-2(4y-1)+2y equation:



4(y+4)=-2(4y-1)+2y
We move all terms to the left:
4(y+4)-(-2(4y-1)+2y)=0
We multiply parentheses
4y-(-2(4y-1)+2y)+16=0
We calculate terms in parentheses: -(-2(4y-1)+2y), so:
-2(4y-1)+2y
We add all the numbers together, and all the variables
2y-2(4y-1)
We multiply parentheses
2y-8y+2
We add all the numbers together, and all the variables
-6y+2
Back to the equation:
-(-6y+2)
We get rid of parentheses
4y+6y-2+16=0
We add all the numbers together, and all the variables
10y+14=0
We move all terms containing y to the left, all other terms to the right
10y=-14
y=-14/10
y=-1+2/5

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