4(y+4)=-2(4y-1)+2y

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Solution for 4(y+4)=-2(4y-1)+2y equation: 



4(y+4)=-2(4y-1)+2y

We move all terms to the left:

4(y+4)-(-2(4y-1)+2y)=0

We multiply parentheses

4y-(-2(4y-1)+2y)+16=0



We calculate terms in parentheses: -(-2(4y-1)+2y), so:

-2(4y-1)+2y

We add all the numbers together, and all the variables

2y-2(4y-1)

We multiply parentheses

2y-8y+2

We add all the numbers together, and all the variables

-6y+2

Back to the equation:

-(-6y+2)



We get rid of parentheses

4y+6y-2+16=0

We add all the numbers together, and all the variables

10y+14=0

We move all terms containing y to the left, all other terms to the right

10y=-14

y=-14/10

y=-1+2/5

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