4(y+4)=-2(7y-4)+8y

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Solution for 4(y+4)=-2(7y-4)+8y equation: 



4(y+4)=-2(7y-4)+8y

We move all terms to the left:

4(y+4)-(-2(7y-4)+8y)=0

We multiply parentheses

4y-(-2(7y-4)+8y)+16=0



We calculate terms in parentheses: -(-2(7y-4)+8y), so:

-2(7y-4)+8y

We add all the numbers together, and all the variables

8y-2(7y-4)

We multiply parentheses

8y-14y+8

We add all the numbers together, and all the variables

-6y+8

Back to the equation:

-(-6y+8)



We get rid of parentheses

4y+6y-8+16=0

We add all the numbers together, and all the variables

10y+8=0

We move all terms containing y to the left, all other terms to the right

10y=-8

y=-8/10

y=-4/5

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