4(y+4)=33

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Solution for 4(y+4)=33 equation: 



4(y+4)=33

We move all terms to the left:

4(y+4)-(33)=0

We multiply parentheses

4y+16-33=0

We add all the numbers together, and all the variables

4y-17=0

We move all terms containing y to the left, all other terms to the right

4y=17

y=17/4

y=4+1/4

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