4(y+4)=42-2y

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Solution for 4(y+4)=42-2y equation: 



4(y+4)=42-2y

We move all terms to the left:

4(y+4)-(42-2y)=0

We add all the numbers together, and all the variables

4(y+4)-(-2y+42)=0

We multiply parentheses

4y-(-2y+42)+16=0

We get rid of parentheses

4y+2y-42+16=0

We add all the numbers together, and all the variables

6y-26=0

We move all terms containing y to the left, all other terms to the right

6y=26

y=26/6

y=4+1/3

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