4(y+5)+y=3(y+5)-2

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Solution for 4(y+5)+y=3(y+5)-2 equation: 



4(y+5)+y=3(y+5)-2

We move all terms to the left:

4(y+5)+y-(3(y+5)-2)=0

We add all the numbers together, and all the variables

y+4(y+5)-(3(y+5)-2)=0

We multiply parentheses

y+4y-(3(y+5)-2)+20=0



We calculate terms in parentheses: -(3(y+5)-2), so:

3(y+5)-2

We multiply parentheses

3y+15-2

We add all the numbers together, and all the variables

3y+13

Back to the equation:

-(3y+13)



We add all the numbers together, and all the variables

5y-(3y+13)+20=0

We get rid of parentheses

5y-3y-13+20=0

We add all the numbers together, and all the variables

2y+7=0

We move all terms containing y to the left, all other terms to the right

2y=-7

y=-7/2

y=-3+1/2

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