4(y+5)-(5y-3)=2(5y+4)-29

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Solution for 4(y+5)-(5y-3)=2(5y+4)-29 equation: 



4(y+5)-(5y-3)=2(5y+4)-29

We move all terms to the left:

4(y+5)-(5y-3)-(2(5y+4)-29)=0

We multiply parentheses

4y-(5y-3)-(2(5y+4)-29)+20=0

We get rid of parentheses

4y-5y-(2(5y+4)-29)+3+20=0



We calculate terms in parentheses: -(2(5y+4)-29), so:

2(5y+4)-29

We multiply parentheses

10y+8-29

We add all the numbers together, and all the variables

10y-21

Back to the equation:

-(10y-21)



We add all the numbers together, and all the variables

-1y-(10y-21)+23=0

We get rid of parentheses

-1y-10y+21+23=0

We add all the numbers together, and all the variables

-11y+44=0

We move all terms containing y to the left, all other terms to the right

-11y=-44

y=-44/-11

y=+4

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