4(y+5)-7y=35

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Solution for 4(y+5)-7y=35 equation: 



4(y+5)-7y=35

We move all terms to the left:

4(y+5)-7y-(35)=0

We add all the numbers together, and all the variables

-7y+4(y+5)-35=0

We multiply parentheses

-7y+4y+20-35=0

We add all the numbers together, and all the variables

-3y-15=0

We move all terms containing y to the left, all other terms to the right

-3y=15

y=15/-3

y=-5

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