4(y+6)=-2(9y-3)+6y

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Solution for 4(y+6)=-2(9y-3)+6y equation: 



4(y+6)=-2(9y-3)+6y

We move all terms to the left:

4(y+6)-(-2(9y-3)+6y)=0

We multiply parentheses

4y-(-2(9y-3)+6y)+24=0



We calculate terms in parentheses: -(-2(9y-3)+6y), so:

-2(9y-3)+6y

We add all the numbers together, and all the variables

6y-2(9y-3)

We multiply parentheses

6y-18y+6

We add all the numbers together, and all the variables

-12y+6

Back to the equation:

-(-12y+6)



We get rid of parentheses

4y+12y-6+24=0

We add all the numbers together, and all the variables

16y+18=0

We move all terms containing y to the left, all other terms to the right

16y=-18

y=-18/16

y=-1+1/8

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