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4(y+6)y=2
We move all terms to the left:
4(y+6)y-(2)=0
We multiply parentheses
4y^2+24y-2=0
a = 4; b = 24; c = -2;
Δ = b2-4ac
Δ = 242-4·4·(-2)
Δ = 608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{608}=\sqrt{16*38}=\sqrt{16}*\sqrt{38}=4\sqrt{38}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{38}}{2*4}=\frac{-24-4\sqrt{38}}{8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{38}}{2*4}=\frac{-24+4\sqrt{38}}{8} $
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