4(y+7)=-5(3y-4)+3y

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Solution for 4(y+7)=-5(3y-4)+3y equation: 



4(y+7)=-5(3y-4)+3y

We move all terms to the left:

4(y+7)-(-5(3y-4)+3y)=0

We multiply parentheses

4y-(-5(3y-4)+3y)+28=0



We calculate terms in parentheses: -(-5(3y-4)+3y), so:

-5(3y-4)+3y

We add all the numbers together, and all the variables

3y-5(3y-4)

We multiply parentheses

3y-15y+20

We add all the numbers together, and all the variables

-12y+20

Back to the equation:

-(-12y+20)



We get rid of parentheses

4y+12y-20+28=0

We add all the numbers together, and all the variables

16y+8=0

We move all terms containing y to the left, all other terms to the right

16y=-8

y=-8/16

y=-1/2

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