4(y+8)+y=3(y+3)-2

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Solution for 4(y+8)+y=3(y+3)-2 equation: 



4(y+8)+y=3(y+3)-2

We move all terms to the left:

4(y+8)+y-(3(y+3)-2)=0

We add all the numbers together, and all the variables

y+4(y+8)-(3(y+3)-2)=0

We multiply parentheses

y+4y-(3(y+3)-2)+32=0



We calculate terms in parentheses: -(3(y+3)-2), so:

3(y+3)-2

We multiply parentheses

3y+9-2

We add all the numbers together, and all the variables

3y+7

Back to the equation:

-(3y+7)



We add all the numbers together, and all the variables

5y-(3y+7)+32=0

We get rid of parentheses

5y-3y-7+32=0

We add all the numbers together, and all the variables

2y+25=0

We move all terms containing y to the left, all other terms to the right

2y=-25

y=-25/2

y=-12+1/2

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