4(y-)-6y=2(y+4)

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Solution for 4(y-)-6y=2(y+4) equation: 



4(y-)-6y=2(y+4)

We move all terms to the left:

4(y-)-6y-(2(y+4))=0

We add all the numbers together, and all the variables

4(+y)-6y-(2(y+4))=0

We add all the numbers together, and all the variables

-6y+4(+y)-(2(y+4))=0

We multiply parentheses

-6y+4y-(2(y+4))=0



We calculate terms in parentheses: -(2(y+4)), so:

2(y+4)

We multiply parentheses

2y+8

Back to the equation:

-(2y+8)



We add all the numbers together, and all the variables

-2y-(2y+8)=0

We get rid of parentheses

-2y-2y-8=0

We add all the numbers together, and all the variables

-4y-8=0

We move all terms containing y to the left, all other terms to the right

-4y=8

y=8/-4

y=-2

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