4(y-1)+3(y-5)=2

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Solution for 4(y-1)+3(y-5)=2 equation: 



4(y-1)+3(y-5)=2

We move all terms to the left:

4(y-1)+3(y-5)-(2)=0

We multiply parentheses

4y+3y-4-15-2=0

We add all the numbers together, and all the variables

7y-21=0

We move all terms containing y to the left, all other terms to the right

7y=21

y=21/7

y=3

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