4(y-1)+3y=9y-(5+2y)+1

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Solution for 4(y-1)+3y=9y-(5+2y)+1 equation:


Simplifying
4(y + -1) + 3y = 9y + -1(5 + 2y) + 1

Reorder the terms:
4(-1 + y) + 3y = 9y + -1(5 + 2y) + 1
(-1 * 4 + y * 4) + 3y = 9y + -1(5 + 2y) + 1
(-4 + 4y) + 3y = 9y + -1(5 + 2y) + 1

Combine like terms: 4y + 3y = 7y
-4 + 7y = 9y + -1(5 + 2y) + 1
-4 + 7y = 9y + (5 * -1 + 2y * -1) + 1
-4 + 7y = 9y + (-5 + -2y) + 1

Reorder the terms:
-4 + 7y = -5 + 1 + 9y + -2y

Combine like terms: -5 + 1 = -4
-4 + 7y = -4 + 9y + -2y

Combine like terms: 9y + -2y = 7y
-4 + 7y = -4 + 7y

Add '4' to each side of the equation.
-4 + 4 + 7y = -4 + 4 + 7y

Combine like terms: -4 + 4 = 0
0 + 7y = -4 + 4 + 7y
7y = -4 + 4 + 7y

Combine like terms: -4 + 4 = 0
7y = 0 + 7y
7y = 7y

Add '-7y' to each side of the equation.
7y + -7y = 7y + -7y

Combine like terms: 7y + -7y = 0
0 = 7y + -7y

Combine like terms: 7y + -7y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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