4(y-1)+5=2-(1-2y)

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Solution for 4(y-1)+5=2-(1-2y) equation: 



4(y-1)+5=2-(1-2y)

We move all terms to the left:

4(y-1)+5-(2-(1-2y))=0

We add all the numbers together, and all the variables

4(y-1)-(2-(-2y+1))+5=0

We multiply parentheses

4y-(2-(-2y+1))-4+5=0



We calculate terms in parentheses: -(2-(-2y+1)), so:

2-(-2y+1)

determiningTheFunctionDomain
-(-2y+1)+2

We get rid of parentheses

2y-1+2

We add all the numbers together, and all the variables

2y+1

Back to the equation:

-(2y+1)



We add all the numbers together, and all the variables

4y-(2y+1)+1=0

We get rid of parentheses

4y-2y-1+1=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0

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