4(y-1)+y=8(y-1)+6

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Solution for 4(y-1)+y=8(y-1)+6 equation: 



4(y-1)+y=8(y-1)+6

We move all terms to the left:

4(y-1)+y-(8(y-1)+6)=0

We add all the numbers together, and all the variables

y+4(y-1)-(8(y-1)+6)=0

We multiply parentheses

y+4y-(8(y-1)+6)-4=0



We calculate terms in parentheses: -(8(y-1)+6), so:

8(y-1)+6

We multiply parentheses

8y-8+6

We add all the numbers together, and all the variables

8y-2

Back to the equation:

-(8y-2)



We add all the numbers together, and all the variables

5y-(8y-2)-4=0

We get rid of parentheses

5y-8y+2-4=0

We add all the numbers together, and all the variables

-3y-2=0

We move all terms containing y to the left, all other terms to the right

-3y=2

y=2/-3

y=-2/3

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