4(y-1)/5=2(y+1)/3

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Solution for 4(y-1)/5=2(y+1)/3 equation: 



4(y-1)/5=2(y+1)/3

We move all terms to the left:

4(y-1)/5-(2(y+1)/3)=0

We calculate fractions


4y/()+(-(2(y+1)*5)/()=0



We calculate terms in parentheses: +(-(2(y+1)*5)/(), so:

-(2(y+1)*5)/(

We multiply all the terms by the denominator


-(2(y+1)*5)



We calculate terms in parentheses: -(2(y+1)*5), so:

2(y+1)*5

We multiply parentheses

10y+10

Back to the equation:

-(10y+10)



We get rid of parentheses

-10y-10

Back to the equation:

+(-10y-10)



We get rid of parentheses

4y/()-10y-10=0

We multiply all the terms by the denominator


4y-10y*()-10*()=0

We add all the numbers together, and all the variables

4y-10y*()=0

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