4(y-1)=-40-8y

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Solution for 4(y-1)=-40-8y equation: 



4(y-1)=-40-8y

We move all terms to the left:

4(y-1)-(-40-8y)=0

We add all the numbers together, and all the variables

4(y-1)-(-8y-40)=0

We multiply parentheses

4y-(-8y-40)-4=0

We get rid of parentheses

4y+8y+40-4=0

We add all the numbers together, and all the variables

12y+36=0

We move all terms containing y to the left, all other terms to the right

12y=-36

y=-36/12

y=-3

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