4(y-1)=2(2y+4)

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Solution for 4(y-1)=2(2y+4) equation: 



4(y-1)=2(2y+4)

We move all terms to the left:

4(y-1)-(2(2y+4))=0

We multiply parentheses

4y-(2(2y+4))-4=0



We calculate terms in parentheses: -(2(2y+4)), so:

2(2y+4)

We multiply parentheses

4y+8

Back to the equation:

-(4y+8)



We get rid of parentheses

4y-4y-8-4=0

We add all the numbers together, and all the variables

-12!=0

There is no solution for this equation

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