4(y-1)=2(y+4)

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Solution for 4(y-1)=2(y+4) equation: 



4(y-1)=2(y+4)

We move all terms to the left:

4(y-1)-(2(y+4))=0

We multiply parentheses

4y-(2(y+4))-4=0



We calculate terms in parentheses: -(2(y+4)), so:

2(y+4)

We multiply parentheses

2y+8

Back to the equation:

-(2y+8)



We get rid of parentheses

4y-2y-8-4=0

We add all the numbers together, and all the variables

2y-12=0

We move all terms containing y to the left, all other terms to the right

2y=12

y=12/2

y=6

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