4(y-10)=6(y+12)

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Solution for 4(y-10)=6(y+12) equation: 



4(y-10)=6(y+12)

We move all terms to the left:

4(y-10)-(6(y+12))=0

We multiply parentheses

4y-(6(y+12))-40=0



We calculate terms in parentheses: -(6(y+12)), so:

6(y+12)

We multiply parentheses

6y+72

Back to the equation:

-(6y+72)



We get rid of parentheses

4y-6y-72-40=0

We add all the numbers together, and all the variables

-2y-112=0

We move all terms containing y to the left, all other terms to the right

-2y=112

y=112/-2

y=-56

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