4(y-2)+(12-6y)=6

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Solution for 4(y-2)+(12-6y)=6 equation: 



4(y-2)+(12-6y)=6

We move all terms to the left:

4(y-2)+(12-6y)-(6)=0

We add all the numbers together, and all the variables

4(y-2)+(-6y+12)-6=0

We multiply parentheses

4y+(-6y+12)-8-6=0

We get rid of parentheses

4y-6y+12-8-6=0

We add all the numbers together, and all the variables

-2y-2=0

We move all terms containing y to the left, all other terms to the right

-2y=2

y=2/-2

y=-1

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