4(y-2)+15=-2(y+5)+6y

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Solution for 4(y-2)+15=-2(y+5)+6y equation: 



4(y-2)+15=-2(y+5)+6y

We move all terms to the left:

4(y-2)+15-(-2(y+5)+6y)=0

We multiply parentheses

4y-(-2(y+5)+6y)-8+15=0



We calculate terms in parentheses: -(-2(y+5)+6y), so:

-2(y+5)+6y

We add all the numbers together, and all the variables

6y-2(y+5)

We multiply parentheses

6y-2y-10

We add all the numbers together, and all the variables

4y-10

Back to the equation:

-(4y-10)



We add all the numbers together, and all the variables

4y-(4y-10)+7=0

We get rid of parentheses

4y-4y+10+7=0

We add all the numbers together, and all the variables

17!=0

There is no solution for this equation

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