4(y-2)+2(2y-1)=6(2y-3)

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Solution for 4(y-2)+2(2y-1)=6(2y-3) equation: 



4(y-2)+2(2y-1)=6(2y-3)

We move all terms to the left:

4(y-2)+2(2y-1)-(6(2y-3))=0

We multiply parentheses

4y+4y-(6(2y-3))-8-2=0



We calculate terms in parentheses: -(6(2y-3)), so:

6(2y-3)

We multiply parentheses

12y-18

Back to the equation:

-(12y-18)



We add all the numbers together, and all the variables

8y-(12y-18)-10=0

We get rid of parentheses

8y-12y+18-10=0

We add all the numbers together, and all the variables

-4y+8=0

We move all terms containing y to the left, all other terms to the right

-4y=-8

y=-8/-4

y=+2

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