4(y-2)+2(y-4)=6(y+5)

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Solution for 4(y-2)+2(y-4)=6(y+5) equation: 



4(y-2)+2(y-4)=6(y+5)

We move all terms to the left:

4(y-2)+2(y-4)-(6(y+5))=0

We multiply parentheses

4y+2y-(6(y+5))-8-8=0



We calculate terms in parentheses: -(6(y+5)), so:

6(y+5)

We multiply parentheses

6y+30

Back to the equation:

-(6y+30)



We add all the numbers together, and all the variables

6y-(6y+30)-16=0

We get rid of parentheses

6y-6y-30-16=0

We add all the numbers together, and all the variables

-46!=0

There is no solution for this equation

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