4(y-2)+2y=30-2(y+7)

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Solution for 4(y-2)+2y=30-2(y+7) equation: 



4(y-2)+2y=30-2(y+7)

We move all terms to the left:

4(y-2)+2y-(30-2(y+7))=0

We add all the numbers together, and all the variables

2y+4(y-2)-(30-2(y+7))=0

We multiply parentheses

2y+4y-(30-2(y+7))-8=0



We calculate terms in parentheses: -(30-2(y+7)), so:

30-2(y+7)

determiningTheFunctionDomain
-2(y+7)+30

We multiply parentheses

-2y-14+30

We add all the numbers together, and all the variables

-2y+16

Back to the equation:

-(-2y+16)



We add all the numbers together, and all the variables

6y-(-2y+16)-8=0

We get rid of parentheses

6y+2y-16-8=0

We add all the numbers together, and all the variables

8y-24=0

We move all terms containing y to the left, all other terms to the right

8y=24

y=24/8

y=3

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