4(y-2)+3(2y-1)=6(2y-1)=6(2y-3)

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Solution for 4(y-2)+3(2y-1)=6(2y-1)=6(2y-3) equation: 



4(y-2)+3(2y-1)=6(2y-1)=6(2y-3)

We move all terms to the left:

4(y-2)+3(2y-1)-(6(2y-1))=0

We multiply parentheses

4y+6y-(6(2y-1))-8-3=0



We calculate terms in parentheses: -(6(2y-1)), so:

6(2y-1)

We multiply parentheses

12y-6

Back to the equation:

-(12y-6)



We add all the numbers together, and all the variables

10y-(12y-6)-11=0

We get rid of parentheses

10y-12y+6-11=0

We add all the numbers together, and all the variables

-2y-5=0

We move all terms containing y to the left, all other terms to the right

-2y=5

y=5/-2

y=-2+1/2

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