4(y-2)+3=-5+4y

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Solution for 4(y-2)+3=-5+4y equation: 



4(y-2)+3=-5+4y

We move all terms to the left:

4(y-2)+3-(-5+4y)=0

We add all the numbers together, and all the variables

4(y-2)-(4y-5)+3=0

We multiply parentheses

4y-(4y-5)-8+3=0

We get rid of parentheses

4y-4y+5-8+3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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