4(y-2)+4=(2y-2)

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Solution for 4(y-2)+4=(2y-2) equation: 



4(y-2)+4=(2y-2)

We move all terms to the left:

4(y-2)+4-((2y-2))=0

We multiply parentheses

4y-((2y-2))-8+4=0



We calculate terms in parentheses: -((2y-2)), so:

(2y-2)

We get rid of parentheses

2y-2

Back to the equation:

-(2y-2)



We add all the numbers together, and all the variables

4y-(2y-2)-4=0

We get rid of parentheses

4y-2y+2-4=0

We add all the numbers together, and all the variables

2y-2=0

We move all terms containing y to the left, all other terms to the right

2y=2

y=2/2

y=1

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