4(y-2)+4=5(-2y-1)+3

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Solution for 4(y-2)+4=5(-2y-1)+3 equation: 



4(y-2)+4=5(-2y-1)+3

We move all terms to the left:

4(y-2)+4-(5(-2y-1)+3)=0

We multiply parentheses

4y-(5(-2y-1)+3)-8+4=0



We calculate terms in parentheses: -(5(-2y-1)+3), so:

5(-2y-1)+3

We multiply parentheses

-10y-5+3

We add all the numbers together, and all the variables

-10y-2

Back to the equation:

-(-10y-2)



We add all the numbers together, and all the variables

4y-(-10y-2)-4=0

We get rid of parentheses

4y+10y+2-4=0

We add all the numbers together, and all the variables

14y-2=0

We move all terms containing y to the left, all other terms to the right

14y=2

y=2/14

y=1/7

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