4(y-2)+7y=-30

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Solution for 4(y-2)+7y=-30 equation:



4(y-2)+7y=-30
We move all terms to the left:
4(y-2)+7y-(-30)=0
We add all the numbers together, and all the variables
7y+4(y-2)+30=0
We multiply parentheses
7y+4y-8+30=0
We add all the numbers together, and all the variables
11y+22=0
We move all terms containing y to the left, all other terms to the right
11y=-22
y=-22/11
y=-2

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