4(y-2)+9y=3(y+4)

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Solution for 4(y-2)+9y=3(y+4) equation: 



4(y-2)+9y=3(y+4)

We move all terms to the left:

4(y-2)+9y-(3(y+4))=0

We add all the numbers together, and all the variables

9y+4(y-2)-(3(y+4))=0

We multiply parentheses

9y+4y-(3(y+4))-8=0



We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We add all the numbers together, and all the variables

13y-(3y+12)-8=0

We get rid of parentheses

13y-3y-12-8=0

We add all the numbers together, and all the variables

10y-20=0

We move all terms containing y to the left, all other terms to the right

10y=20

y=20/10

y=2

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