4(y-2)-2=-2(-7y+4)-6y

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Solution for 4(y-2)-2=-2(-7y+4)-6y equation: 



4(y-2)-2=-2(-7y+4)-6y

We move all terms to the left:

4(y-2)-2-(-2(-7y+4)-6y)=0

We multiply parentheses

4y-(-2(-7y+4)-6y)-8-2=0



We calculate terms in parentheses: -(-2(-7y+4)-6y), so:

-2(-7y+4)-6y

We add all the numbers together, and all the variables

-6y-2(-7y+4)

We multiply parentheses

-6y+14y-8

We add all the numbers together, and all the variables

8y-8

Back to the equation:

-(8y-8)



We add all the numbers together, and all the variables

4y-(8y-8)-10=0

We get rid of parentheses

4y-8y+8-10=0

We add all the numbers together, and all the variables

-4y-2=0

We move all terms containing y to the left, all other terms to the right

-4y=2

y=2/-4

y=-1/2

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