4(y-2)-4=-3(-5y+3)-5y

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Solution for 4(y-2)-4=-3(-5y+3)-5y equation: 



4(y-2)-4=-3(-5y+3)-5y

We move all terms to the left:

4(y-2)-4-(-3(-5y+3)-5y)=0

We multiply parentheses

4y-(-3(-5y+3)-5y)-8-4=0



We calculate terms in parentheses: -(-3(-5y+3)-5y), so:

-3(-5y+3)-5y

We add all the numbers together, and all the variables

-5y-3(-5y+3)

We multiply parentheses

-5y+15y-9

We add all the numbers together, and all the variables

10y-9

Back to the equation:

-(10y-9)



We add all the numbers together, and all the variables

4y-(10y-9)-12=0

We get rid of parentheses

4y-10y+9-12=0

We add all the numbers together, and all the variables

-6y-3=0

We move all terms containing y to the left, all other terms to the right

-6y=3

y=3/-6

y=-1/2

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