4(y-2)-5(y+1)=y-13

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Solution for 4(y-2)-5(y+1)=y-13 equation: 



4(y-2)-5(y+1)=y-13

We move all terms to the left:

4(y-2)-5(y+1)-(y-13)=0

We multiply parentheses

4y-5y-(y-13)-8-5=0

We get rid of parentheses

4y-5y-y+13-8-5=0

We add all the numbers together, and all the variables

-2y=0

y=0/-2

y=0

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