4(y-2)-6y=-2(3y+

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Solution for 4(y-2)-6y=-2(3y+ equation: 



4(y-2)-6y=-2(3y+

We move all terms to the left:

4(y-2)-6y-(-2(3y+)=0

We add all the numbers together, and all the variables

4(y-2)-6y-(-2(+3y)=0

We add all the numbers together, and all the variables

-6y+4(y-2)-(-2(+3y)=0

We multiply parentheses

-6y+4y-(-2(+3y)-8=0

We add all the numbers together, and all the variables

-2y-(-2(+3y)-8=0

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