4(y-2)-8=-2(-8y+1)-4y

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Solution for 4(y-2)-8=-2(-8y+1)-4y equation: 



4(y-2)-8=-2(-8y+1)-4y

We move all terms to the left:

4(y-2)-8-(-2(-8y+1)-4y)=0

We multiply parentheses

4y-(-2(-8y+1)-4y)-8-8=0



We calculate terms in parentheses: -(-2(-8y+1)-4y), so:

-2(-8y+1)-4y

We add all the numbers together, and all the variables

-4y-2(-8y+1)

We multiply parentheses

-4y+16y-2

We add all the numbers together, and all the variables

12y-2

Back to the equation:

-(12y-2)



We add all the numbers together, and all the variables

4y-(12y-2)-16=0

We get rid of parentheses

4y-12y+2-16=0

We add all the numbers together, and all the variables

-8y-14=0

We move all terms containing y to the left, all other terms to the right

-8y=14

y=14/-8

y=-1+3/4

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