4(y-2)-8=-3(5y+2)-7y

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Solution for 4(y-2)-8=-3(5y+2)-7y equation:



4(y-2)-8=-3(5y+2)-7y
We move all terms to the left:
4(y-2)-8-(-3(5y+2)-7y)=0
We multiply parentheses
4y-(-3(5y+2)-7y)-8-8=0
We calculate terms in parentheses: -(-3(5y+2)-7y), so:
-3(5y+2)-7y
We add all the numbers together, and all the variables
-7y-3(5y+2)
We multiply parentheses
-7y-15y-6
We add all the numbers together, and all the variables
-22y-6
Back to the equation:
-(-22y-6)
We add all the numbers together, and all the variables
4y-(-22y-6)-16=0
We get rid of parentheses
4y+22y+6-16=0
We add all the numbers together, and all the variables
26y-10=0
We move all terms containing y to the left, all other terms to the right
26y=10
y=10/26
y=5/13

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