4(y-2)-8=-7(-3y+2)-y

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Solution for 4(y-2)-8=-7(-3y+2)-y equation: 



4(y-2)-8=-7(-3y+2)-y

We move all terms to the left:

4(y-2)-8-(-7(-3y+2)-y)=0

We multiply parentheses

4y-(-7(-3y+2)-y)-8-8=0



We calculate terms in parentheses: -(-7(-3y+2)-y), so:

-7(-3y+2)-y

We add all the numbers together, and all the variables

-1y-7(-3y+2)

We multiply parentheses

-1y+21y-14

We add all the numbers together, and all the variables

20y-14

Back to the equation:

-(20y-14)



We add all the numbers together, and all the variables

4y-(20y-14)-16=0

We get rid of parentheses

4y-20y+14-16=0

We add all the numbers together, and all the variables

-16y-2=0

We move all terms containing y to the left, all other terms to the right

-16y=2

y=2/-16

y=-1/8

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