4(y-2)=4+2(y-1)

Solution for 4(y-2)=4+2(y-1) equation:

4(y-2)=4+2(y-1)

We move all terms to the left:

4(y-2)-(4+2(y-1))=0

We multiply parentheses

4y-(4+2(y-1))-8=0


We calculate terms in parentheses: -(4+2(y-1)), so:

4+2(y-1)

determiningTheFunctionDomain
2(y-1)+4

We multiply parentheses

2y-2+4

We add all the numbers together, and all the variables

2y+2

Back to the equation:

-(2y+2)


We get rid of parentheses

4y-2y-2-8=0

We add all the numbers together, and all the variables

2y-10=0

We move all terms containing y to the left, all other terms to the right

2y=10

y=10/2

y=5